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Area Under Force-Extension Graph
Area Under Force-Extension Graph. You are invited to keep searching for learning materials here. When the force is removed from a material it will contract.

In a spring) when it is stretched or compressed. Calculate this area between the required extensions. Identify sections of the graph where the force changes at a constant rate over a certain distance.
View Solution > The Area Of Force And Time Graph Represents.
(½f is average force) and equal to the elastic potential energy epe stored in the material. The area under a graph of force against distance (or extension, if it's a spring) represents the work done by that force. In a spring) when it is stretched or compressed.
Since It Sounds Like You're Talking About A Spring, You Should Know That The Area Would Represent The Work Done To Stretch The Spring That Distance, And Also Represents The Amount Of Elastic Potential Energy Contained By The Spring.
This is only true for linear relationships though, like hooke's law, as the area under the line is a triangle and the formula for the area of a triangle, 1/2 bh, is. So the area under the curve is. Area under the line = epe (strain energy) per unit volume.
If You Load The Spring By Hanging Weights Off The End And Measure The Net Stretch, Then F Is Independent And X Is.
For each value of force applied, the extension x is recorded. Identify sections of the graph where the force changes at a constant rate over a certain distance. * f=dp/dt then , fdt = dp * impulse= average force × time * impulse of a force is a measure of the total effect of the force.
Al Is The Volume Of The Wire So This Formula Reduces To.
Elastic potential energy is defined as the energy stored within a material (e.g. A wire is stretched by applying increasing values of force f. This chapter has no learning materials.
The Area X Represents The Net Work Done Or The Thermal Energy Dissipated In The Material;
Or, since f = kx (where k is the stiffness constant of the sample): * impulse = change in momentum * according to impulse momentum theorem states that linear momentum can. If the force is constant you can use this equation, but if the force is varying you couldn't just use this, but now we derived this.
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